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  1. assuming angle btwn wall and ground is 90 degrees, this makes it a right triangle problem.

    sq rt((25**2) – (7**2)) = 24 (vert distance that ladder is up wall)
    then, after the 4 ft “slip”,
    24 – 4 = 20 is distance up wall (vert)

    solve for new distance from wall (Horiz)
    sq rt((25**2) – (20**2)) = 15

    difference between old distance and new distance is what the “slip” was
    15 – 7 = 8 ft

  2. I get 8 ft. The initial vertical dimension is 24 ft.

    If it slips 4 ft vertically, the new vertical dimension is 20 ft, making the new horizontal leg of 15 ft. Original horizontal was 7 ft, so it has slipped 8ft.

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